Android ListView帶CheckBox實現單選

這個應該是個經常會遇到的需求，網上找了很多的demo感覺說的有點太長於是自己抽空干脆記錄一下，目前我實現listView帶CheckBox單選主要用兩種方法
1，用一個bean記錄狀態，每次getView的時候去判斷這個bean的狀態
2，判斷點擊的position是否跟getView的position一致，這種辦法耦合性較低不建議使用

第1種方法：

首先是我們的bean：

public class Bean {
    private boolean isChecked;
    private String msg = "這是一條測試數據";

    public Bean(){

    }
    public Bean(boolean isCheched) {
        this.isChecked = isCheched;
    }
    public boolean isChecked() {
        return isChecked;
    }
    public void setChecked(boolean isChecked) {
        this.isChecked = isChecked;
    }
    public String getMsg() {
        return msg;
    }
    public void setMsg(String msg) {
        this.msg = msg;
    } 
}

然後在getView的時候判斷狀態

public View getView(int position, View convertView, ViewGroup parent) {
        ViewHolder mViewHolder;
        if(convertView == null){
            convertView = mInfater.inflate(R.layout.list_item, null);
            mViewHolder = new ViewHolder(convertView);
            convertView.setTag(mViewHolder);
        }else{
            mViewHolder = (ViewHolder) convertView.getTag();
        }
        mViewHolder.mTextView.setText(mDatas.get(position).getMsg());
        if(mDatas.get(position).isChecked()){//狀態選中
            mViewHolder.mCheckBox.setChecked(true);
        }else{
            mViewHolder.mCheckBox.setChecked(false);
        }
        return convertView;
    }

這樣我們就能通過bean的狀態來控制checkBox的選中與否了，但是onItemCLick的時候的操作才是關鍵

public class MainActivity extends ActionBarActivity {
    private ListView mListView;
    private ListAdapter mAdapter;
    private List mDatas;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        mListView = (ListView) findViewById(R.id.main_listView);
        mDatas = new ArrayList();
        for (int i = 0; i < 20; i++) {
            if(i == 0){//默認選中第一個
                mDatas.add(new Bean(true));
                continue;
            }
            mDatas.add(new Bean(false));
        }
        mAdapter = new ListAdapter(this, mDatas);
        mListView.setAdapter(mAdapter);
        mListView.setOnItemClickListener(mOnItemClickListener);
    }

    private final OnItemClickListener mOnItemClickListener = new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView adapterView, View view, int position, long arg3) {
            for (Bean bean : mDatas) {//全部設為未選中
                bean.setChecked(false);
            }
            mDatas.get(position).setChecked(true);//點擊的設為選中
            mAdapter.notifyDataSetChanged();

        }
    };
}

XML

<linearlayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="horizontal">

    <textview android:id="@+id/main_list_item_text" android:layout_width="0dp" android:layout_height="match_parent" android:textcolor="@android:color/black" android:layout_weight="1" android:gravity="center_vertical">

    <checkbox android:id="@+id/main_list_item_checkBox" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center_vertical" android:backgroundtintmode="multiply" android:layout_marginright="10dp" android:clickable="false" android:focusableintouchmode="false" android:focusable="false">
</checkbox></textview></linearlayout>

於是這樣ListView的CheckBox就能實現單選了

第二種：

這種辦法不推薦使用

public class MainActivity extends ActionBarActivity {
    private ListView mListView;
    private ListAdapter mAdapter;
    private List mDatas;
    public static int pos;//記錄選中的position
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        mListView = (ListView) findViewById(R.id.main_listView);
        mDatas = new ArrayList();
        for (int i = 0; i < 20; i++) {
            if(i == 0){
                mDatas.add(new Bean(true));
                continue;
            }
            mDatas.add(new Bean(false));
        }
        mAdapter = new ListAdapter(this, mDatas);
        mListView.setAdapter(mAdapter);
        mListView.setOnItemClickListener(mOnItemClickListener);
    }

    private final OnItemClickListener mOnItemClickListener = new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView adapterView, View view, int position, long arg3) {
            pos = position;
            mAdapter.notifyDataSetChanged();
        }
    };

}

getView的時候判斷MainActivity的pos是否等於getView的position

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        ViewHolder mViewHolder;
        if(convertView == null){
            convertView = mInfater.inflate(R.layout.list_item, null);
            mViewHolder = new ViewHolder(convertView);
            convertView.setTag(mViewHolder);
        }else{
            mViewHolder = (ViewHolder) convertView.getTag();
        }
        mViewHolder.mTextView.setText(mDatas.get(position).getMsg());
        if(MainActivity.pos == position){//MainActivity的pos是否等於position
            mViewHolder.mCheckBox.setChecked(true);
        }else{
            mViewHolder.mCheckBox.setChecked(false);
        }
        return convertView;
    }

不推薦使用第二種辦法，這種辦法會讓程序的耦合性變得很低，並且全局變量始終會有一個Class 對象的句柄指向它除非這個Class對象要被回收了否則靜態變量是不會被GC掉

以上僅是個人用法，當然也有其他辦法實現，看個人的喜好吧